I want to check if array contains object or not. I am not trying to compare values just want to check in my array if object is present or not?
Ex.
$arr = ['a','b','c'] // normal
$arr = [{ id: 1}, {id: 2}] // array of objects
$arr = [{id: 1}, {id:2}, 'a', 'b'] // mix values
So how can i check if array contains object
You can use some method which tests whether at least one element in the array passes the test implemented by the provided function.
let arr = [{id: 1}, {id:2}, 'a', 'b'];
let exists = arr.some(a => typeof a == 'object');
console.log(exists);
some method provide a callback test function for ever item from the array. The test function check if array item is object. The condition is if typeof a is object.some method returns true if at least one item from the array satifiy the condition.I want to check if array contains object or not
Use some to simply check if any item of the array has value of type "object"
var hasObject = $arr.some( function(val){
return typeof val == "object";
});
var hasObject = function(arr) {
for (var i=0; i<arr.length; i++) {
if (typeof arr[i] == 'object') {
return true;
}
}
return false;
};
console.log(hasObject(['a','b','c']));
console.log(hasObject([{ id: 1}, {id: 2}]));
console.log(hasObject([{id: 1}, {id:2}, 'a', 'b']));You could count the objects and use it for one of the three types to return.
function getType(array) {
var count = array.reduce(function (r, a) {
return r + (typeof a === 'object');
}, 0);
return count === array.length
? 'array of objects'
: count
? 'mix values'
: 'normal';
}
console.log([
['a', 'b', 'c'],
[{ id: 1 }, { id: 2 }],
[{ id: 1 }, { id: 2 }, 'a', 'b']
].map(getType));With a type check on array
const hasObject = a => Array.isArray(a) && a.some(val => typeof val === 'object')
