Error: when fetching value from a json data via php

Question

Json data(pincodes.json):

[{
    "officename": "Netajinagar B.O",
    "pincode": 744207,
    "taluk": "Hut Bay",
    "districtname": "South Andaman",
    "statename": "ANDAMAN \u0026 NICOBAR ISLANDS"
}, {
    "officename": "Tushnabad B.O",
    "pincode": 744103,
    "taluk": "Port Blair",
    "districtname": "South Andaman",
    "statename": "ANDAMAN \u0026 NICOBAR ISLANDS"
}, {
    "officename": "Uttara B.O",
    "pincode": 744209,
    "taluk": "Rangat",
    "districtname": "North And Middle Andaman",
    "statename": "ANDAMAN \u0026 NICOBAR ISLANDS"
}]

PHP code:

<?php

$string  = file_get_contents("pincodes.json");
$json_s =  json_decode($string);


foreach($json_s[0] as $item)
{
    if($item->pincode == "686563")
    {
        echo $item->officename;
    }else{
        echo "Item not found";
    }
}

I am trying to fetch a particular value of an element(officename) based on the criteria(pincode=686563) but when executes getting error

Invalid argument supplied for foreach()

What does print_r($json_s[0]); gives me you?

hungrykoala
– hungrykoala

2017-10-17 08:41:08 +00:00
Commented Oct 17, 2017 at 8:41 — hungrykoala
– hungrykoala, Commented Oct 17, 2017 at 8:41

madalinivascu · Accepted Answer · 2017-10-17 08:46:07Z

4

Remove [0] you want to loop over the elements in the array not over the properties of the first object, make sure your file has valid json,and php is able to read it

foreach($json_s as $item)
{
    if($item->pincode == "686563")
    {
        echo $item->officename;
    }else{
        echo "Item not found";
    }
}

demo :https://ideone.com/uUdNLt

edited Oct 17, 2017 at 8:46

answered Oct 17, 2017 at 8:39

madalinivascu

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