Extracting a specific value from command-line output using powershell

Question

Here's the problem: I want to query subversion for the revision number of a repository, and then create a new directory with the revision number in its name (for example, "Build763").

The command "svn info" outputs a number of label\value pairs, delimited by colons. For example

Path: c#
URL: file:///%5Copdy-doo/Archive%20(H)/Development/CodeRepositories/datmedia/Development/c%23
Repository UUID: b1d03fca-1949-a747-a1a0-046c2429f46a
Revision: 58
Last Changed Rev: 58
Last Changed Date: 2011-01-12 11:36:12 +1000 (Wed, 12 Jan 2011)

Here is my current code which solves the problem. Is there a way to do this with less code? I'm thinking that with the use of piping you could do this with one or two lines. I certainly shouldn't have to use a temporary file.

$RepositoryRoot = "file:///%5Cdat-ftp/Archive%20(H)/Development/CodeRepositories/datmedia"
$BuildBase="/Development/c%23"
$RepositoryPath=$RepositoryRoot + $BuildBase

# Outputing the info into a file
svn info $RepositoryPath | Out-File -FilePath svn_info.txt

$regex = [regex] '^Revision: (\d{1,4})'

foreach($info_line in get-content "svn_info.txt")
    {
        $match = $regex.Match($info_line);
        if($match.Success)
        {
            $revisionNumber = $match.Groups[1];
            break;
        }
    }


"Revision number = " + $revisionNumber;

bahrep · Accepted Answer · 2012-12-22 08:51:00Z

3

Here's one way:

    $revisionNumber = svn info $RepositoryPath |
     select-string "^revision" |
      foreach {$_.line.split(":")[1].trim()}

    if ($revisionNumber){"Revision number = " + $revisionNumber

}

edited Dec 22, 2012 at 8:51

bahrep

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answered Jan 14, 2011 at 2:30

mjolinor

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Comments

Andrew Shepherd · Accepted Answer · 2011-01-14 03:32:23Z

2

Taking mjolinor's suggestion, I'm finally going with:

$revisionNumber = (svn info $RepositoryPath | select-string '^Revision: (\d+)$').Matches[0].Groups[1].Value

Cool! One line of code. (It took two hours to write, but hey)

edited Jan 14, 2011 at 3:32

answered Jan 14, 2011 at 3:05

Andrew Shepherd

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6 Comments

mjolinor Over a year ago

They make you dig for that capture, don't they?

Jaykul Over a year ago

Well, you could just use (svn info $RepositoryPath) -Replace '^Revision: (\d+)$','$1' to get at the capture ;)

mjolinor Over a year ago

That's better. I'll have to remember that.

Andrew Shepherd Over a year ago

@Jaykul: That only works if "(svn info $RepositoryPath)" returns one line. I've tried this and you get the revision line with just the number, but you get all of the other lines (URL, repository ID etc) as well.

Mike D Over a year ago

You could simplify this even more: (svn info $RepositoryPath | select-string "^Revision").ToString().Split(":")[1].Trim()

|

Jaykul · Accepted Answer · 2011-01-15 15:17:31Z

2

For what it's worth, you could use ConvertFrom-PropertyString

answered Jan 15, 2011 at 15:17

Jaykul

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Comments

Lazy Badger · Accepted Answer · 2012-12-22 11:06:42Z

0

If you can create and use Working Copy of URL (WC), you can

svnversion WC: will output clean number of WC-revision

> svnversion trunk

34
With SubWCRrev convert template-file with SubWCRrev-keywords into bat-file (subwcrev WC tpl-file bat-file) with RevNo, substituted in needed place (inside mkdir options) and call resulted bat for performing operation

answered Dec 22, 2012 at 11:06

Lazy Badger

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