I have and array, and I want to convert it into an if conditional.
$array = ['check 1', 'check 2', 'check 3'];
I want the final result to work like this:
if ($var == 'check 1' || $var == 'check 2' || $var == 'check 3') {
// Do here.
}
I don't have any inspiration, I already searched for convert array to if condition but I couldn't find anything.
How can I convert the array into an if conditional?
Instead of multiple || (OR) conditions use in_array()
if (in_array($var, $array)) {
// do here
}
Output:-https://eval.in/914346
If you want to check multiple variables against array then do like this:-
if (in_array($var, $array) || in_array($var1, $array)){
//do here
}
Output:- https://eval.in/914351
Note:- If you can clarify more about all your variables and what conditions you want for all those variables, you will get more accurate answer
Loop through array and check in_array like this:
$array = ( 'check 1', 'check 2', 'check 3' );
foreach($array as $k => $v)
{
$flag = "false";
if(in_array($v,$array))
{
$flag = "true";
}
}
So from above code, is any of the value exist in array, the variable $flag will have string value "true".
<?php
$array = array( "mango", "grapes","apple");
//let you have to find apple
if(in_array('masngo',$array) || in_array('mango',$array)){
echo "FIND";
//OR WHATEVER YOU WANT TO DO
}else{
echo "Not Found";
}
Try to run HERE
in_arraycan be useful to youin_arrayif (in_array($var, $array) || in_array($var1, $array)){ //do something }