Regex - Convert pattern from php to Java

Question

In php I can check if a word is in a String like that

$muster = "/\b($word)\b/i";
if(preg_match($muster, $text)) {
        return true;
}

Example:

$word = "test";
$text = "This is a :::test!!!";

Returns true

I tried converting this into Java:

if (Pattern.matches("(?i)\\b(" + word + ")\\b", text)) {
   return true;
}

The same example :

String word = "test";
String text = "This is a :::test!!!";

would return false

What am I missing here? :(

Pattern.matches("(?i).*\\b" + word + "\\b.*" as matches means match complete input in Java. — anubhava
– anubhava, Commented Dec 7, 2017 at 19:35
You can use indexOf to see if string contains a specific word. — whatamidoingwithmylife
– whatamidoingwithmylife, Commented Dec 7, 2017 at 19:36

Youcef LAIDANI · Accepted Answer · 2017-12-07 19:36:47Z

4

You have to use Matcher and call find like this :

Pattern pattern = Pattern.compile("(?i)\\b(" + word + ")\\b");
Matcher matcher = pattern.matcher(text);
System.out.println(matcher.find());// true if match false if not

answered Dec 7, 2017 at 19:36

Youcef LAIDANI

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