Array structure with PHP

Question

I'm facing a array structure problem here.

Why this array

$plans = array(
    'id'   => 'free', 
    'name' => 'Free', 
    'sums' => array(
        'usd' => 0,
    ),
    'id'   => 'trial', 
    'name' => 'Trial', 
    'sums' => array(
        'usd' => 0,
    ),
);

returns me only this (last result of my array):

Array
(
    [id] => trial
    [name] => Trial
    [sums] => Array
        (
            [usd] => 0
        )

)

Any help with this will be very appreciated.

Thanks a lot.

You can't use the same key more than once in an associative array. You need to use an array of arrays. — Alex Howansky
– Alex Howansky, Commented Jan 12, 2018 at 19:21

John Conde · Accepted Answer · 2018-01-12 19:28:25Z

7

That is because you overwrite the array keys in each array item effectively removing the value before it. You need an array of arrays for this data:

$plans = array(
    array(
        'id'   => 'free', 
        'name' => 'Free', 
        'sums' => array(
            'usd' => 0,
        )
    ),
    array(
        'id'   => 'trial', 
        'name' => 'Trial', 
        'sums' => array(
            'usd' => 0,
        )
    )
);

edited Jan 12, 2018 at 19:28

answered Jan 12, 2018 at 19:21

John Conde

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