PHP return numeric name from json

Question

I have code:

$json = file_get_contents('https://api.coinmarketcap.com/v1/ticker/?limit=0');
$coins = json_decode($json, true);
foreach($coins as $coin) {
  echo $coin->24h_volume_usd;
}

Script return me error:

Parse error: syntax error, unexpected '24' (T_LNUMBER), expecting identifier (T_STRING) or variable (T_VARIABLE) or '{' or '$'...

Yes, I know I can't used name JSON with number, but I can't change 24h_volume_usd to for example: h_volume_usd, because this is value download from other page (ink).

Change the object to an array? Perhaps that will work? You can do that with json_decode(), but that part is missing from your code. — KIKO Software
– KIKO Software, Commented Jan 21, 2018 at 21:02
@KIKOSoftware Not work, when I change to: echo $coin['24h_volume_usd']; I have error: Cannot use object of type stdClass as array — major697
– major697, Commented Jan 21, 2018 at 21:04
You need to change the object to an array, of course. For instance like Aniket Sahrawat says. — KIKO Software
– KIKO Software, Commented Jan 21, 2018 at 21:05

trincot · Accepted Answer · 2018-01-21 21:10:00Z

2

When an object key starts with digits, you need to wrap it as string literal in braces, like this:

$coin->{"24h_volume_usd"};

edited Jan 21, 2018 at 21:10

answered Jan 21, 2018 at 21:08

trincot

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Niels Vanhorenbeeck · Accepted Answer · 2018-01-21 21:06:49Z

1

You can decode the json-string into an associative array, by setting the second parameter to true.

$coins = json_decode($jsonString, true);
foreach($coins as $coin) {
  echo $coin['24h_volume_usd'];
}

answered Jan 21, 2018 at 21:06

Niels Vanhorenbeeck

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