Getting TypeError: float argument required in Python 2.7

Question

I am passing a floating exponent value to a python function and later using it:

def estimateFit(infile, fsrmin):
    test=isfloat(fsrmin)
    print "fsrmin test for isfloat: %s" %test
    flimit = 30e9;
    print "flimit = %.3e" %flimit
    float(fsrmin)
    print "fsrmin = %.3e" %fsrmin

I am calling this function from another python program as:

     fsrmin = sys.argv[3]
R, I, w = srf.estimateFit(infile,fsrmin)

I am always getting this error:

>     print "fsrmin = %.3e" %fsrmin 
TypeError: float argument required, not str

As you can see I tried to convert to float in the program. Anything I am missing

I am doing it inside the final function estimateFit.. line 6 — dgarg
– dgarg, Commented Feb 7, 2018 at 14:50

hiro protagonist · Accepted Answer · 2018-02-07 14:54:55Z

1

you do not assign fsrmin to float(fsrmin). i suggest you use:

fsrmin = sys.argv[3]    # fsrmin is a str for now
fsrmin = float(fsrmin)  # here we convert to float
R, I, w = srf.estimateFit(infile,fsrmin)

the statement float(fsrmin) does not change the variable fsrmin. it will raise a ValueError if the string fsrmin can not be interpreted as float.

edited Feb 7, 2018 at 14:54

answered Feb 7, 2018 at 8:15

hiro protagonist

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2 Comments

dgarg Over a year ago

But I am already doing this before the print, but still getting the error

dgarg Over a year ago

Oh, sorry I misunderstood the first time. I will try it and confirm

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