replace the presence of certain characters in a string in javascript or angularjs

Question

I have a string named pageList= [[],[2567,2568,],[2569,2570,2571,2537,],[2538,2586,2587,2588,],[2589,2590,2591,2592,2593,]] I need to remove the presnce of [], with (empty) and ,[] with (empty) and ,] with ] . I tried the code

              pageList = pageList.replace(/,]/g,']');                 
              pageList = pageList.replace(/[]/g,''); 
              pageList = pageList.replace(/[/]/g,'');

But its is replacing the ,] with ] but removing the ,[] and [], is not working.The output I am getting now is [[],[2567,2568],[2569,2570,2571,2537],[2538,2586,2587,2588],[2589,2590,2591,2592,2593]]

void · Accepted Answer · 2018-02-26 05:03:24Z

2

You do not need regex here as it is not a string.

This being an array so extra , will automatically be removed. To remove [] you can use .filter() here

var pageList=  [[],[2567,2568,],[2569,2570,2571,2537,],[2538,2586,2587,2588,],[2589,2590,2591,2592,2593,]];

pageList = pageList.filter(el => el.length!==0)

console.log(pageList);

PS: If your data is in string format then you might need to parse it to array by doing JSON.parse(pageList);

answered Feb 26, 2018 at 5:03

void

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1 Comment

Senchu Thomas Over a year ago

In this code if the string is only [] it will not remove anything

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