How to convert Strings in Swift?

Question

I've two cases where I need to convert strings to different formats.

for ex:

case 1:
  string inputs: abc, xyz, mno, & llr   // All Strings from a dictionary
  output: ["abc","xyz", "mno", "llr"]  //I need to get the String array like this.

But when I use this code:

 var stringBuilder:[String] = [];
 for i in 0..<4 {
   stringBuilder.append("abc"); //Appends all four Strings from a Dictionary
 }

print(stringBuilder); //Output is 0: abc, 1:xyz like that, how to get desired format of that array like ["abc", "xyz"];

Real usage:

let arr = Array(stringReturn.values);
//print(arr)  // Great, it prints ["abc","xyz"];
let context = JSContext()
context?.evaluateScript(stringBuilder)   
let testFunction = context?.objectForKeyedSubscript("KK")
let result = testFunction?.call(withArguments:arr); // Here when I debugger enabled array is passed to call() like 0:"abc" 1:"xyz". where as it should be passed as above print.

Secondly how to replace escape chars in swift: I used "\" in replaceOccurances(of:"\\'" with:"'"); but its unchanged. why and how to escape that sequnce.

case 2:
  string input: \'abc\'
  output: 'abc'

Can you edit your question to contain the definition of your dictionary? — d.felber
– d.felber, Commented Mar 5, 2018 at 10:41
var stringReturn:Dictionary = Dictionary<String,Any>(); is the definition. — Group
– Group, Commented Mar 5, 2018 at 10:42

d.felber · Accepted Answer · 2018-03-05 10:50:55Z

1

To get all values of your dictionary as an array you can use the values property of the dictionary:

let dictionary: Dictionary<String, Any> = [
    "key_a": "value_a",
    "key_b": "value_b",
    "key_c": "value_c",
    "key_d": "value_d",
    "key_e": 3
]

let values = Array(dictionary.values)
// values: ["value_a", "value_b", "value_c", "value_d", 3]

With filter you can ignore all values of your dictionary that are not of type String:

let stringValues = values.filter({ $0 is String }) as! [String]
// stringValues: ["value_a", "value_b", "value_c", "value_d"]

With map you can transform the values of stringValues and apply your replacingOccurrences function:

let adjustedValues = stringValues.map({ $0.replacingOccurrences(of: "value_", with: "") })
// adjustedValues: ["a", "b", "c", "d"]

edited Mar 5, 2018 at 10:50

answered Mar 5, 2018 at 10:19

d.felber

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6 Comments

Group Over a year ago

You output is like this: LazyMapCollection<Dictionary<String, Any>, Any>(_base: ["key_a": "value_a", "key_b": "value_b"]

d.felber Over a year ago

Well strange. I tested my code against Swift 3.2 and Swift 4 before posting. Maybe you are missing some information from your setup?

Group Over a year ago

When I print the values its printed ["abc", "xyz"] but when I pass it like find(values) then after hitting debug point, it shows like 0:abc, 1:xyz

d.felber Over a year ago

That is because the value at index 0 has the value abc and the value at index 1 has xyz I don't see the problem here. Maybe you can tell us more what you are trying to accomplish by extending your question.

Group Over a year ago

see updated question. There call() need an array like ["xyz","abc"]

|

jms · Accepted Answer · 2018-03-05 12:20:38Z

0

Why not try something like this? For part 1 of the question that is:

var stringReturn: Dictionary = Dictionary<String,Any>()
stringReturn = ["0": "abc","1": "def","2": "ghi"]
print(stringReturn)

var stringBuilder = [String]()
for i in stringReturn {
  stringBuilder.append(String(describing: i.value))
}
print(stringBuilder)

Also, part 2 seems to be trivial unless I'm not mistaken

var escaped: String = "\'abc\'"
print(escaped)

edited Mar 5, 2018 at 12:20

answered Mar 5, 2018 at 12:14

jms

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Comments

piet.t · Accepted Answer · 2018-03-06 07:21:57Z

0

case 1: I have Implemented this solutions, Hope this will solve your problem

   let dict: [String: String] = ["0": "Abc", "1": "CDF", "2": "GHJ"]                
   var array: [String] = []

for (k, v) in dict.enumerated() {
    print(k)
    print(v.value)
    array.append(v.value)  
}
print(array)

case 2:

    var str = "\'abc\'"
    print(str.replacingOccurrences(of: "\'", with: ""))

edited Mar 6, 2018 at 7:21

piet.t

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answered Mar 5, 2018 at 10:14

Anil Kumar

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2 Comments

Group Over a year ago

I need a array of format ["abc","xyz","mno"] where in your code will produce this.

Group Over a year ago

Please read my question carefully. I already did what you posted.

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