Sorting string arrays based on the number present in the element

Question

I have to sort a string array based on the number.

Example

["1.READ","10.CREATE","3.sfg","2.dfd","12.dqwe"];

Desired Result

["1.READ","2.dfd","3.sfg","10.CREATE","12.dqwe"];

My Code

var arr = ["1.READ","10.CREATE","3.sfg","2.dfd","12.dqwe"];
var arr2 = arr.map( a => a.split('.').map( n => +n+100000 ).join('.') ).sort().map( a => a.split('.').map( n => +n-100000 ).join('.') );
console.log(arr);
console.log(arr2);

Eddie · Accepted Answer · 2018-03-21 06:14:02Z

2

You can just split and convert the first element to Number

var arr = ["1.READ", "10.CREATE", "3.sfg", "2.dfd", "12.dqwe"];

var arr2 = arr.sort((a, b) => {
  return Number(a.split(".")[0]) - Number(b.split(".")[0]);
});

console.log(arr2);

The code above will also sort the first variable. If you you only want arr2 to be sorted, you can:

var arr = ["1.READ", "10.CREATE", "3.sfg", "2.dfd", "12.dqwe"];

var arr2 = [...arr]; //Spread the array so that it will not affect the original
arr2.sort((a, b) => {
  return Number(a.split(".")[0]) - Number(b.split(".")[0]);
});

console.log(arr);
console.log(arr2);

answered Mar 21, 2018 at 6:14

Eddie

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Nina Scholz · Accepted Answer · 2018-03-21 06:15:41Z

2

You could split and take only the first part. Then take the delta for sorting.

var array = ["1.READ", "10.CREATE", "3.sfg", "2.dfd", "12.dqwe"];

array.sort((a, b) => a.split(".")[0] - b.split(".")[0]);

console.log(array);

answered Mar 21, 2018 at 6:15

Nina Scholz

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1 Comment

user5818995 Over a year ago

@NinaScholz as clean as it can be :)

ThangTD · Accepted Answer · 2018-03-21 06:26:16Z

1

Here it is:

var arr = ["1.READ","10.CREATE","3.sfg","2.dfd","12.dqwe"];

arr.sort(function(a, b) {
    return a.split('.')[0] - b.split('.')[0];
});

console.log(arr)
// ["1.READ", "2.dfd", "3.sfg", "10.CREATE", "12.dqwe"]

This answer base on built in array sort function, with customizable compare logic. Check this out for more detail: Javascript Array Sort

Cheers,

answered Mar 21, 2018 at 6:26

ThangTD

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