How ffmpeg is command executed in this code

Question

want to know how the ffmpeg command is executed for taking screenshot in this code. I am not able to figure out when screenshot is created, by which function or by which line it is done.

  $ffmpeg = '/usr/bin/ffmpeg';
        $video  = $sourceUrl;// the input video file
        $thumbId = uniqid();
        $thumbId .= ".jpg";
        // where you'll save the image
        $image = "uploads/$thumbId";
        // default time to get the image
        $second = 1;
        // get the duration and a random place within that
        $cmd = "$ffmpeg -i $video 2>&1";
        if (preg_match('/Duration: ((\d+):(\d+):(\d+))/s', `$cmd`, $time)) {
            $total = ($time[2] * 3600) + ($time[3] * 60) + $time[4];
            $second = rand(1, ($total - 1));
        }

        // get the screenshot
        $cmd = "$ffmpeg -i $video -deinterlace -an -ss $second -t 00:00:01 -r 1 -y -s 120x90 -vcodec mjpeg -f mjpeg $image 2>&1";
        $return = `$cmd`;
        $thumbLink = "";

@Dan thanks for edit want to write proper spellings .

XMen
– XMen

2011-02-09 07:11:17 +00:00
Commented Feb 9, 2011 at 7:11 — XMen
– XMen, Commented Feb 9, 2011 at 7:11

Dan Grossman · Accepted Answer · 2011-02-09 07:05:45Z

3

This line executes the command which you stored in the variable $cmd:

    $return = `$cmd`;

In PHP, the backtick is the execution operator, and its use is identical to calling shell_exec.

answered Feb 9, 2011 at 7:05

Dan Grossman

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