(2011..1995).to_a
returns an array
(Time.now.year.to_i..1995).to_a
doesn't. Why?
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1both of these statements return empty array for me. ruby 1.8.7p302Eimantas– Eimantas2011-02-09 13:55:29 +00:00Commented Feb 9, 2011 at 13:55
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Both return an empty array, as Eimantas says. However, if you you reverse the items in the range so that 1995 is first, they both return the expected array. Ranges aren't really meant going backwards.Kyle Heironimus– Kyle Heironimus2011-02-09 14:44:38 +00:00Commented Feb 9, 2011 at 14:44
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you should indicate which Ruby version are you usingtokland– tokland2011-02-09 16:45:38 +00:00Commented Feb 9, 2011 at 16:45
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(Time.now.year.to_i).downto(1995).to_aMahesh– Mahesh2014-04-02 11:35:28 +00:00Commented Apr 2, 2014 at 11:35
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5 Answers
try
> 2011.downto(1995).to_a
=> [2011, 2010, 2009, 2008, 2007, 2006, 2005, 2004, 2003, 2002, 2001, 2000, 1999, 1998, 1997, 1996, 1995]
Comments
You can use this
(Time.now.year.to_i).downto(1995).to_a
Comments
I don't see that either work. Here's irb on WinXP...
irb(main):009:0> (2011..1995).to_a
=> []
irb(main):010:0> (Time.now.year.to_i..1995).to_a
=> []
irb(main):011:0>
Comments
(1995..Time.now.year.to_i).to_a works. End should large than begin.
Comments
I cannot replicate your results. Both of these expressions return an array.
Of course, since both of the ranges are empty, the expressions will always return an empty array, but that's not relevant to your question.
