$useridtofind= 123;
$users=array();
while ($data = mysql_fetch_array ($result))
{
$userid = $data['userid'];
$age = $data['age'];
$gender = $data['gender'];
$dob = $data['dob'];
$users[$userid] => array(
'age'=> $age,
'gender'=> $gender,
'dob' => $dob
)
}
$useridtofind=123;
for($v=0; $v< count($users); $v++)
{
if($users[$v]== $useridtofind)
{
//how to go with grab value of age, gender, dob here?
}
}
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2 Answers
You seem to be using the user id as the index of the user in the array. If this is the case, you shouldn't be using a for loop, you should just check if the key exists within the array:
$useridtofind = 123;
if (array_key_exists($useridtofind, $users)) {
$user = $users[$useridtofind];
echo "User exists: ", $user['age'], '/', $user['gender'], '/', $user['dob'];
} else {
echo "User doesn't exist";
}