i want to check if an array containes other array in ExtJs i tried this but without success
if( [2,1] in [1,2,3]){
console.log("true"); }
i know that i can do it manualy but is there a direct methode
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Are both arrays guaranteed to be unique? Does order matter?Evan Trimboli– Evan Trimboli2018-04-04 23:57:40 +00:00Commented Apr 4, 2018 at 23:57
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Possible duplicate of Javascript 2d array indexOfTaki– Taki2018-04-05 00:01:32 +00:00Commented Apr 5, 2018 at 0:01
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no order doesn't matter EvanAmor.o– Amor.o2018-04-05 00:42:02 +00:00Commented Apr 5, 2018 at 0:42
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i saw it it's not the same TakiAmor.o– Amor.o2018-04-05 00:42:21 +00:00Commented Apr 5, 2018 at 0:42
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@Amor.o you should use Ext.Array utility object, have a look to my answerLellisMoon– LellisMoon2018-04-05 15:39:23 +00:00Commented Apr 5, 2018 at 15:39
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3 Answers
var arr1=[2,1],
arr2=[1,2,3];
if(Ext.Array.merge(arr1,arr2).length===arr2.length){
console.log('HELLO!');
}
If you're using Extjs, using this method you can win without functions and cicles
Simply merging the arrays.
Comments
You need to loop over the Array to check if the values are in it:
function inArray(v, a){
for(var i=0,l=a.length; i<l; i++){
if(a[i] === v){
return true;
}
}
return false;
}
function allInArray(t, a){
for(var i=0,l=t.length; i<l; i++){
if(!inArray(t[i], a)){
return false;
}
}
return true;
}
var yourArray = [1, 2, 3], tests = [2, 1];
console.log(allInArray(tests, yourArray));
console.log(allInArray([2, 4, 1], yourArray));
// another way
function allIn(t, a){
return t.length === t.map(x => +a.includes(x)).reduce((n, v) => n+v);
}
console.log(allIn(tests, yourArray));
console.log(allIn([3, 4], yourArray));
1 Comment
Amor.o
thank u i already have a solution like that but i ask if there is a direct solution , that's means with a predefined function
In extjs you have Ext.each function to loop out through the array
var array_1 = [2,1];
var array_2 = [1,2,3];
Ext.each(array_1,function(value_of_arr1){
if(array_2.indexOf(value_of_arr1) == -1){
console.log('array_1 value doesnt exist');
return;
}else{
console.log('array_1 value does exist');
return;
}
});
In above code the -1 is returned from the if condition if the value of array_1 is not found in the array_2
if value is found the array index in which the value resides is returned
