Set css variable with HTML5 color picker in Angular 5?

Question

I have an Angular 5 application with items styled in CSS with CSS variables, as in

--color-links: #0000ff;
a { color: var(--color-links); }

So, I was trying to wire up an HTML5 color picker to allow changing this variable on the fly.

I saw this article which showcases this pen where the author is using some simple JS to do something like I am trying to do, but with document.addEventListener. I was trying to come up with a pure Angular/HTML5 method.

So, I created a picker:

    <div class="form-group">
        <label for="color-picker-link">Link color</label>
        <input type="color"
               id="color-picker-link"
               (change)="setColor()"
               [(value)]="linkColor">
      </div>

And in my Component, I create the variable linkColor and setting it to #0000ff. That part works, the picker defaults to blue.

public linkColor = '#0000ff';
setColor() {
  console.log('value', this.linkColor);
}

However, the variable always logs as the original 30000ff even though the picker obviously changes.

So, what I need to do is get the value the picker was changed to. Not sure why it's not working.

Also, the sample Codepen I linked to above uses this function to set the variable value once retrieved, although I don't think it would work in an Angular app:

function setThemeVar(name, value, unit) {
  var rootStyles = document.styleSheets[0].cssRules[0].style;
  rootStyles.setProperty('--theme-' + name, value + (unit || ''));
}

If I can solve getting the value from the picker on change, and then fire a function passing that retrieved value I can probably figure out the rest.

Ashish Jain · Accepted Answer · 2018-04-06 17:54:48Z

1

To get the selected value from the picker use ngModelChange event with ngModel directive.

<input type="color"
               id="color-picker-link"
               (ngModelChange)="setColor($event)"
               [ngModel]="linkColor">

setColor(newColor) {
  console.log('value', newColor);
  this.linkColor = newColor;
}

answered Apr 6, 2018 at 17:54

Ashish Jain

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