How to compare these array object orders are equal.
this.arrayOne = [
{ "data": "India", "seq_id": 1 },
{ "data": "Japan", "seq_id": 2 },
{ "data": "USA", "seq_id": 3 }
]
this.arrayTwo = [
{ "data": "India", "seq_id": 1 },
{ "data": "Japan", "seq_id": 2 },
{ "data": "USA", "seq_id": 3 }
]
Anyone can solve the problem..!?
This code checks if both arrays have the same order. To compare the objects in the arrays it checks if two objects have the same number of properties and all their properties are equal (considering that all properties are of primitive types).
let arrayOne = [
{ "match_value": "India", "seq_id": 1 },
{ "match_value": "Japan", "seq_id": 2 },
{ "match_value": "USA", "seq_id": 3 }
];
let arrayTwo = [
{ "match_value": "India", "seq_id": 1 },
{ "match_value": "Japan", "seq_id": 2 },
{ "match_value": "USA", "seq_id": 3 }
];
let equal = arrayOne.every((item, i) => {
let keys = Object.keys(item);
return keys.length === Object.keys(arrayTwo[i]).length &&
keys.every(key => arrayTwo[i][key] === item[key]);
});
console.log(equal);
item is defined as an arrow function parameter. And the above script works as expected. Make sure you have no typos in your code. And what version of typescript do you use?try something like this :
let a = [
{ "match_value": "India", "seq_id": 1 },
{ "match_value": "Japan", "seq_id": 2 },
{ "match_value": "USA", "seq_id": 3 }
]
let b = [
{ "match_value": "India", "seq_id": 1 },
{ "match_value": "Japan", "seq_id": 2 },
{ "match_value": "USA", "seq_id": 3 }
]
function compare(a, b):boolean{
let flag = a.length ;
for (let i = 0, len = a.length; i < len; i++) {
if (a[i].match_value === b[i].match_value) {
if (a[i].seq_id === b[i].seq_id) {
flag --;
}
}
}
if(flag)
return false;
else
return true;
}
console.log(compare(a,b));
Sometimes i take the easy approach.
function compare(a:any , b:any) {
return JSON.stringify(a) === JSON.stringify(b);
}
this works for me in Angular 13.
