I have an array like:
var array = [1, 2, undefined, undefined, 7, undefined]
and need to replace all undefined values with "-". The result should be:
var resultArray = [1, 2, "-", "-", 7, "-"]
I think there is a simple solution, but I couldn't find one.
You could check for undefined and take '-', otherwise the value and use Array#map for getting a new array.
var array = [1, 2, undefined, undefined, 7, undefined],
result = array.map(v => v === undefined ? '-' : v);
console.log(result);For a sparse array, you need to iterate all indices and check the values.
var array = [1, 2, , , 7, ,],
result = Array.from(array, v => v === undefined ? '-' : v);
console.log(result);You can use Array.map
var array = [1, 2, undefined, undefined, 7, undefined];
var newArray = array.map(x => x !== undefined ? x : "-");
console.log(newArray);You can map the values and return - if undefined.
let array = [1, 2, undefined, undefined, 7, undefined]
let result = array.map(o => o !== undefined ? o : '-');
console.log(result);
var newArray = array.map(function(val) {
if (typeof val === 'undefined') {
return '-';
}
return val;
});
function SampleArray() {
var Array = [];
var array = [1, 2, undefined, undefined, 7, undefined];
for (var i = 0; array.length > i; i++) {
var Value;
if (array[i] == undefined) {
Value = '-';
} else {
Value = array[i];
}
Array.push(Value);
}
}
Try using this -
array.forEach(function(part,index,Arr){ if(!Arr[index])Arr[index]='-'})
You can use functional programming map function:
let array = [1, 2, undefined, undefined, 7, undefined];
let array2 = array.map(e => e === undefined ? e='-' : e);
Try:
while((index = array.indexOf(undefined)) > -1){array[index] = "-";}
"-"
this will search for the index of the value you are searching for, and replace it with "-"
