PHP: Find highest index of numeric array that has missing elements [duplicate]

Question

Say I have the following array:

$n[5] = "hello";
$n[10]= "goodbye";`

I would like to find out the highest index of this array. In Javascript, I could do $n.length - 1 which would return 10. In PHP, though, count($n) returns 2, which is the number of elements in the array.

So how to get the highest index of the array?

Death-is-the-real-truth · Accepted Answer · 2018-05-01 12:35:24Z

2

Use max() and array_keys()

echo max(array_keys($n));

Output:-https://eval.in/997652

edited May 1, 2018 at 12:35

answered May 1, 2018 at 12:25

Death-is-the-real-truth

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4 Comments

Ariel Over a year ago

Thanks! If there is no way to do it with a single command, this will do.

Ariel Over a year ago

array_keys is 1 command, then max is 2. So this is 2 steps (in a single line), where Javascript does it in one: [].length. No hassle, just interesting difference for me between php and javascript.

Death-is-the-real-truth Over a year ago

@Ariel then i can say that $n.length is one step and -1 from it will second step. :):)

Ariel Over a year ago

True. But usually this is going to be useful in a loop, in which case: for (i = 0; i < n.length; i++).... so only 1 step ;-)

Daniel1147 · Accepted Answer · 2018-05-01 12:31:30Z

1

$n = [];
$n[5] = "hello";
$n[10]= "goodbye";

// get the list of key
$keyList = array_keys($n);

// get the biggest key
$maxIndex = max($keyList);

echo $n[$maxIndex];

output

goodbye

edited May 1, 2018 at 12:31

answered May 1, 2018 at 12:25

Daniel1147

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