My string is
str = "my string is this one"
and my array is
arr = ["no", "nothing", "only", "is"]
So, my string includes the is in the value of my array, I want to get the result true
How can I do this?
I want to use include? met
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3 Answers
To check when the whole word is included case sensitive:
(str.split & arr).any?
#⇒ true
Case insensitive:
[str.split, arr].map { |a| a.map(&:downcase) }.reduce(&:&).any?
#⇒ true
To check if it includes any of arr anyhow:
arr.any?(&str.method(:include?))
#⇒ true
answered May 2, 2018 at 18:23
Aleksei Matiushkin
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Comments
(str.downcase.split & arr.map(&:downcase)).any?
#=> false
If it is known that all letters are of the same case.
(str.split & arr).any?
#=> false
Comments
This uses a Regular expression. The good news is that it is generated for you - no syntax to learn. Other good news: it traverses the string only once.
re = Regexp.union(arr) #your own regular expression without screws or bolts
p re.match?(str) # => true
1 Comment
Cary Swoveland
I believe you need word boundaries. For example,
str = "not"; arr = ["no"] should not match. (Easy fix, nice approach.)