Regex for url resource part

Question

Context

I have code that takes an url path and replaces path params with '*'. All my urls follow JSON API naming convention. All valid url resource parts follow next rules:

Member names SHOULD start and end with the characters “a-z” (U+0061 to U+007A)
Member names SHOULD contain only the characters “a-z” (U+0061 to U+007A), “0-9” (U+0030 to U+0039), and the hyphen minus (U+002D HYPHEN-MINUS, “-“) as separator between multiple words.

The pass param usually is an id (number, uuid, guid, etc).

Here are several examples of transformations:

/user/e09e4f9f-cfcd-4a23-a88f-b9f2f265167f/info -> /user/*/info
/user/e09e4f9f-cfcd-4a23-a88f-b9f2f265167f -> /user/*
/user/1 -> /user/*

What I have

/^[a-z][a-z0-9-]*[a-z]$/

The issues is that it doesn't handle uuid as a path param.

Here is my function that parses the url (sorry don't have time to create a jsfiddle):

const escapeResourcePathParameters = resource => resource
  .substr(resource.startsWith('/') ? 1 : 0)
  .split('/')
  .reduce((url, member) => {
     const match = member.match(REGEX.JSONAPI_RESOURCE_MEMBER);

     const part = match
         ? member
         : '*';

     return `${url}/${part}`;
}, '');

Questions

I need a regex that follows the rules above and works for the examples above.

UPD: I've added my function that I use to parse urls. To test your regex, just replace it with REGEX.JSONAPI_RESOURCE_MEMBER and pass the url like /user/e09e4f9f-cfcd-4a23-a88f-b9f2f265167f/info, it should return /user/*/info

what is "path param" (that need to be replaced by '*') - how to 'recognize it' ? — Kamil Kiełczewski
– Kamil Kiełczewski, Commented May 11, 2018 at 15:17
how does 1 in /user/1 comply to the Member names SHOULD start and end with the characters “a-z” ? — Matus Dubrava
– Matus Dubrava, Commented May 11, 2018 at 15:19
@MatusDubrava Because 1 in this case is a parameter not a member of the API. — Derek 朕會功夫
– Derek 朕會功夫, Commented May 11, 2018 at 15:20
@MatusDubrava it doesn't cause, 1 is a path parameter, it shouldn't follow the rules, and I need to replace it — Vladyslav Sheruda
– Vladyslav Sheruda, Commented May 11, 2018 at 15:20
That's like the issue, I need to find resource parts that are not follow the rules and replace them — Vladyslav Sheruda
– Vladyslav Sheruda, Commented May 11, 2018 at 15:21

tjadli · Accepted Answer · 2018-05-11 16:00:28Z

1

i am guessing you are looking for a regex to capture the UUID :

this should be working in javascript :

/[a-z][a-z0-9]+[-]+[a-z0-9-]+[a-z]/

I suppose a UUID Should have at least two words, so at least one "-"

let a = "/user/e09e4f9f-cfcd-4a23-a88a/info"

const match = a.match(/[a-z][a-z0-9]+[-]+[a-z0-9-]+[a-z]/)

console.log(match[0])

So for your code, it should be something like

 const escapeResourcePathParameters = resource => resource
  .substr(resource.startsWith('/') ? 1 : 0)
  .split('/')
  .reduce((url, member) => {
    // with  REGEX.JSONAPI_RESOURCE_MEMBER = /[a-z][a-z0-9]*[-]+[a-z0-9-]+[a-z]/
    return `${url}/${member.replace(REGEX.JSONAPI_RESOURCE_MEMBER, '*')}`;

 }, '');

edited May 11, 2018 at 16:00

answered May 11, 2018 at 15:23

tjadli

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3 Comments

Vladyslav Sheruda Over a year ago

I don;t think so, the user part is just an example, it can be /info/user/1/list/5

Vladyslav Sheruda Over a year ago

and how .* handles the rules described above?

Vladyslav Sheruda Over a year ago

>I suppose a UUID Should have at least two words, so at least one "-" correct, but this doesn't work, I'll share a bit of code that parses the url

builder-7000 · Accepted Answer · 2018-05-11 15:56:42Z

0

You could use look-arounds:

(?<=\/)[a-z][a-z0-9-]*[a-z](?=\/)

As noted in my comment, no need to use the anchors ^ nor $. Also escape slash \/. The regex wil match the pattern [a-z][a-z0-9-]*[a-z] only when surrounded by slashes.

/user/e09e4f9f-cfcd-4a23-a88f-b9f2f265167f/info # result:  /*/*/info
/user/e09e4f9f-cfcd-4a23-a88f-b9f2f265167f      # result:  /*/e09e4f9f-cfcd-4a23-a88f-b9f2f265167f
/user/1                                         # result: /*/1

To match UUIDs use:

(?<=\/)[a-z0-9-]{8}-(?:[a-z0-9-]{4}-){3}[a-z0-9-]{12}(?=\/)

The UUID format is described here: https://en.wikipedia.org/wiki/Universally_unique_identifier#Format

edited May 11, 2018 at 15:56

answered May 11, 2018 at 15:48

builder-7000

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