Sort multiple array key's in ascending and descending order, string with number

Question

I have an array of JavaScript objects:

This is not a duplicate question. Because, I have an array of objects that has 2 keys (key, count). I wanted to sort, key in ascending( which is string) AND value in descending(which is number) order.

 var array = [
  {"count":7,"key":"a"},
  {"count":10,"key":"b"},
  {"count":5,"key":"c"},
  {"count":10,"key":"a"},
  {"count":3,"key":"d"}
];

Desired Output:

     var array = [
      {"count":10,"key":"a"},
      {"count":10,"key":"b"},
      {"count":7,"key":"a"},
      {"count":5,"key":"c"},
      {"count":3,"key":"d"}
    ];

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => (b.count - a.count)));

key sort as ascending

count sort as descending

I have used array.sort((a, b) => (b.count - a.count)) method for sorting count. but, Can't figure out how to sort both the keys of object.

By the answer you marked as correct, it is exactly a duplicate. — Matt Way
– Matt Way, Commented May 16, 2018 at 11:30

Mihai Alexandru-Ionut · Accepted Answer · 2018-05-16 10:51:32Z

3

You have to use logical || operator in combination with localeCompare function.

|| operator will only consider the second component if the b.count - a.count result is zero.

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => b.count - a.count || a.key.localeCompare(b.key)));

edited May 16, 2018 at 10:51

answered May 16, 2018 at 10:48

Mihai Alexandru-Ionut

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Nikhil Aggarwal · Accepted Answer · 2018-05-16 10:40:55Z

2

Try following

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => {
  if(a.count === b.count) return a.key.localeCompare(b.key);
  return b.count - a.count;
}));

answered May 16, 2018 at 10:40

Nikhil Aggarwal

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