Assigning values from one array to another in Powershell without encountering null index when de-referencing elements

Question

I have an array with fields (a multi dimensional array, if I am correct), my aim is to create another array based on elements filtered from the first.

However when I come to deference $arr2 by looking at its first element $arr[0], I get the error message:

Cannot index into a null array

Can someone please provide me with some advise as to the most elegant way of resolving this.

for ($i=0; $i -lt $arr1.length; $i++) {
    if ($arr1[$i].source -eq $SomeValue) {
        $arr2 += @( $arr1[$i] )
    }
}

I guess that's because you haven't initialized $arr2 anywhere. Trying putting $arr2 = @() at the top of your code. — Vivek Kumar Singh
– Vivek Kumar Singh, Commented May 29, 2018 at 13:00
Personally I may need a little more information to completely understand your situation. First, based on your code, $arr1 is an array of objects. Not a multi-dimensional array. Second, what is the goal of forcing elements to be added to $arr2 as arrays instead of simply adding the element as it is $arr2 += $arr1[$i]? — EBGreen
– EBGreen, Commented May 29, 2018 at 13:01

f6a4 · Accepted Answer · 2018-05-29 20:12:59Z

1

$arr2 = @( $arr1 | Where { $_.source -eq $someValue } )

edited May 29, 2018 at 20:12

answered May 29, 2018 at 18:19

f6a4

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1 Comment

ChrisAdkin Over a year ago

This is what I went with in the end $arr1 = < call function to generate array of objects > $arr2 = $arr1.where({ ([string]$_.Source) -eq $FilterString })

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