Calling the same function within another via parameter

Question

I have an existential doubt, I can not do that within a parameter that becomes a callback function enter and manipulate the same function, I have no idea what this would be like, but in this example it shows it.

<?php

class where{


    public function show_sql( $params ){

        if( is_numeric($params) ){
            echo "Number $params <br />";
        }elseif( is_callable($params) ) { // here validate if function
            // get_defined_vars() <--- I get the variables but I can not manipulate same function
        }
        return $this;
    }


}

$DB = new where;

$DB->show_sql(12)
    ->show_sql(13)
    ->show_sql(function ($object){
        $object->show_sql(14);
    });
?>

The result would be

Number 12 
Number 13

But the number 14 is not shown and I call it in the same function. I want to have the same result as Laravel does in this example: https://laravel.com/docs/master/queries#where-clauses go to Parameter Grouping

Someone could help me ?

@MagnusEriksson ->show_sql(function ($object){ $object->show_sql(14); }); I think that here I am making the parameter a callback so that I can use the same function again but I do not know how to call the same function again — LΞИIИ
– LΞИIИ, Commented Jun 5, 2018 at 5:29
@Bdloul - is_callable() works for closures as well. It will return true as long as the variable can be called as a function. — M. Eriksson
– M. Eriksson, Commented Jun 5, 2018 at 5:33

M. Eriksson · Accepted Answer · 2018-06-05 05:32:21Z

1

You need to execute your callback.

You can use call_user_func_array() and pass the object as parameter:

}elseif( is_callable($params) ) {
    call_user_func_array($params, [$this]);
}

answered Jun 5, 2018 at 5:32

M. Eriksson

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4 Comments

LΞИIИ Over a year ago

thanks this worked !, how can I know when the callback starts and when it ends if I have several functions inside? example:

$DB->show_sql(12)     ->show_sql(13)     ->show_sql(function ($object){         $object->show_sql(14); $object->show_sql(15);      })

Could I use a Boolean variable to know when the callback starts and when the series ends? to get a result like that Number 12 Number 13 ( Number 14 Number 15 ) Number 16 where "()" are string.. How could I do it?

M. Eriksson Over a year ago

Just echo the parentheses before and after the execution. Something like echo ' ( '; call_user_func_array($params, [$this]); echo ' ) ';. If this answer solved the issue in the question, feel free to accept it.

LΞИIИ Over a year ago

it does not work, the result is: Number 12 Number 13 Number 14 Number 15 ()Number 16 I want the result to be Number 12 Number 13 ( Number 14 Number 15 ) Number 16 with function call like this

$DB->show_sql(12)     ->show_sql(13)     ->show_sql(function ($object){         $object->show_sql(14);         $object->show_sql(15);     })     ->show_sql(16);

should I use a public variable of the class where the string is concatenated? How could it be?

M. Eriksson Over a year ago

If you do as I suggested, it will work: 3v4l.org/EmL4V (if you check my previous comment, you see that I echoed one before the call and one after) - Also, before asking more questions, you might want to accept the answer I've already given you?

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