Assume I have the string:
10,11,12,13,14,ABC,DEF,GHI,66
I am looking to run a regex against it to only return 0-9 and the "," characters, essentially stripping anything else out.
I have looked at Regex.Replace, but something isn't quite right with it. My code below:
Regex reg = new Regex(@"[0-9,]+");
string input = reg.Replace(input, delegate(Match m)
{
return String.Empty;
});
How can I make this work?
Do you just want a ^ in that?
input = Regex.Replace(input, @"[^0-9,]+", "");
@"([^0-9,]+,)" instead. Oh, gotta love regular expression syntax.
a12v3,7y8z -> 123,78. If it isn't, it is much simpler - you can dimple match for all [0-9]+. Also, your regex requires a comma, it will not work on the last word (though that one is simple).
Would a match collection give you more control?
Using \d+[^,] you can get a collection of digits?
You could then loop through your collection and recreate your desired string.
using linq you could do the following:
var input = "10,11,12,13,14,ABC,DEF,GHI,66";
Regex re = new Regex(@"\d+[^,]");
input = (from Match m in re.Matches(input) select m.Value).Aggregate("", (acc, item) => acc + "," + item).TrimStart(',');
\d+ with [A-Za-z]+ if you just wanted the letters.How about this:
var testString = "10,11,12,13,14,ABC,DEF,GHI,66";
var split = testString.Split(',');
var result = String.Join(",", split.Where(element => element.All(c => Char.IsDigit(c))).ToArray());
I think that you may do it without regular expressions via analysis of what is required for your characters in set [0123456789,].
string input = reg.Replace(input, "");(orString.Emptyif you like it better). It is very curious you've found the callback variation before a simple string replace...10,11,12,13,14,66so removingABC,DEF,GHI,