JS Combined regex not working [duplicate]

Question

When I do it like this:

areport = areport.replace(/\\"/g, "");
areport = areport.replace(/{/g, "");
areport = areport.replace(/}/g, "");
areport = areport.replace(/[\[\]']+/g, "");
areport = areport.replace(/,/g, "");
areport = areport.replace(/"/g, "");
areport = areport.replace(/\\/g, "");
areport = areport.replace(/null/g, "");

It works, however when I do it like this:

areport = areport.replace(/\[\]\/\\,\{\}\"null/g, "");

It doesn't. I've checked it with 'regex101' and it returns "g modifier: global. All matches (don't return after first match)" so I attempted to rearrange the order but to no avail. Please show me the error of my ways. Thanks.

Can you provide us with an example of the input and the desired output? — Wild Beard
– Wild Beard, Commented Jun 19, 2018 at 16:45
The input: let areport = JSON.stringify(localStorage.getItem("report")); — fyrfterjr
– fyrfterjr, Commented Jun 19, 2018 at 16:51

TFrazee · Accepted Answer · 2018-06-19 16:42:13Z

1

Your code is looking for the following exact string: []/\,{}"null. If you want to look for any instance of any of those characters, you need to put them in square brackets, which function to search for "any of these characters." The null can then be put after an or | character.

/[[\]/\\,{}"]|null/g

answered Jun 19, 2018 at 16:42

TFrazee

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fyrfterjr · Accepted Answer · 2018-06-19 17:28:16Z

0

Thank you all for your help. The answer was to add '|' in between each character

areport = areport.replace(/\\|\{|\}|\[|\]|\\|,|\"|null/g, "");

so that regex knew to look for any global instance instead of the particular order. It's interesting that in I couldn't find any reference to that in any of the resources that I checked (must not have looked hard enough). Additional thanks to TFrazee for pointing that out.

answered Jun 19, 2018 at 17:28

fyrfterjr

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1 Comment

Wiktor Stribiżew Over a year ago

It is exactly my /null|[\\",[\]'{}]+/g pattern.

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