sorting different types of variables in an array

Question

Here we have 2 types of variables in an array and one being an integer while the other being a string , I am trying to sort the array via alphabetical order or by the length of the string but it keeps detecting the integer over the string first.

    const val=[{
      x:"second",
      y:2
     },{
      x:"first",
      y:1
    }];   
    function compare(a,b){return b.length-a.length};
    val.sort(compare);
    console.log(val);

Objects don't have a length property unless explicitly defined (which is not the case here) — CertainPerformance
– CertainPerformance, Commented Jul 12, 2018 at 7:52
"variables in an array": you mean (property) values. Variables are different things. — trincot
– trincot, Commented Jul 12, 2018 at 7:58

Ankit · Accepted Answer · 2018-07-12 07:54:46Z

1

    const val=[{
      x:"second",
      y:2
     },{
      x:"first",
      y:1
    }];   
    function compare(a,b){return a.x.length-b.x.length};
    val.sort(compare);
    console.log(val);

You need to compare the property and not the object. Also you might want to handle all the scenarios of -1, 0 and 1 for the callback. I'll leave that to you. Have a look at existing similar questions.

answered Jul 12, 2018 at 7:54

Ankit

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Comments

aravind_reddy · Accepted Answer · 2018-07-12 07:58:18Z

0

you are finding the length of the object not the object key x so you need to change your a.length to a.x.length and b.length to b.x.length

answered Jul 12, 2018 at 7:58

aravind_reddy

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