How to read PHP function into an array

Question

I have the following function snippets which calculate the bi-monthly payment schedule. I need to be able to ready the values as individual array element to be inserted into MYSQL database. How do I achieve this?

function calculatePaymentSchedule($d1, $months){
    $date = new DateTime($d1);

    // call second function to add the months
    $newDate = $date->add(addMonths($months, $date));

    //formats final date to Y-m-d form
    $dateReturned = $newDate->format('Y-m-d'); 

    return $dateReturned;
}

$startDate = '2018-5-15'; 
$duration = 12;
$paymentCount = $duration + 2;

for($i =0; $i < $paymentCount; $i++){
    if($i % 2 == 0 && $i != 0){
        $final = calculatePaymentSchedule($startDate, $i);
        echo $final.'<br>';
    }
}

current state output:

Use $final[] = calculatePaymentSchedule($startDate, $i); so you fill the $final array with the individual results and reference the array elements for inserts into your database. — lovelace
– lovelace, Commented Jul 12, 2018 at 14:06
Already did that. First element resulted in 2018-07-15 2018-07-15 2018-07-15 2018-07-15 2018-07-15 2018-07-15 instead of 2018-07-15. — Ralph
– Ralph, Commented Jul 12, 2018 at 14:15

Lukas · Accepted Answer · 2018-07-12 14:33:53Z

1

initalize array at top:

all_dates = array();

in for loop :

$final = calculatePaymentSchedule($startDate, $i);
array_push($all_dates, $final);

answered Jul 12, 2018 at 14:33

Lukas

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2 Comments

Ralph Over a year ago

Thanks Lukas. Your solution is already implemented; it worked. You deserve +1

Lukas Over a year ago

I'm glad i cloud help!

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