Look for existing object in array

Question

I have the following Array

[{cityName: "Gauteng"}, {cityName: "cape town"}, {cityName: "Durban"}]

I am trying to check if a value matches "cityName" in any of the objects .eg I have a set value as "Durban" and it should return true as Durban exists in on of the objects

My attempt is below however I am getting a false value even if the cityName exists

  test() {
   var x = this.getCities;
   var doesExist = x.some((el) => { el.cityName === "Durban"});
   console.log(doesExist);
  }

hi { el.cityName === "Durban"} should be { return el.cityName === "Durban"} or can be just `el.cityName === "Durban". You are very close :-) — D. Seah
– D. Seah, Commented Jul 31, 2018 at 4:40

Sajeetharan · Accepted Answer · 2018-07-31 04:23:24Z

2

It works fine. Probably your x variable is null. I guess getCities should be a function

var x = this.getCities();

DEMO

let cities = [{cityName: "Gauteng"}, {cityName: "cape town"}, {cityName: "Durban"}];
let isFound = cities.some(t=>t.cityName ==='Durban');
console.log(isFound);

answered Jul 31, 2018 at 4:23

Sajeetharan

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Pranay Rana · Accepted Answer · 2018-07-31 04:45:23Z

1

you can try this also

let cities = [{cityName: "Gauteng"}, {cityName: "cape town"}, {cityName: "Durban"}];
const index = cities.findIndex(t=>t.cityName ==='Durban');
if(index !== -1 )
  console.log("found");

or find as suggested in commen t

let cities = [{cityName: "Gauteng"}, {cityName: "cape town"}, {cityName: "Durban"}];
const foundelement = cities.find(t=>t.cityName ==='Durban');
if(foundelement)
  console.log("found");

edited Jul 31, 2018 at 4:45

answered Jul 31, 2018 at 4:37

Pranay Rana

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1 Comment

lemieuxster Over a year ago

or even .find and then just check for null

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