I have two arrays
array1 = [
{name: "samsung", views: 1200},
{name: "apple", views: 200}
]
array2 = [
{name: "samsung-1234", views: 200},
{name: "apple-2332", views: 200},
{name: "samsung-6543", views: 400},
{name: "samsung-9876", views: 600}
]
How can I get sumsung has 3 types and apple has 1 type in array2.
Thanks. Any help is appreciated
You can use .filter() on array2 and specify name from array1 to build the filter and .includes() to compare names
let array1 = [
{name: "samsung", views: 1200},
{name: "apple", views: 200}
];
let array2 = [
{name: "samsung-1234", views: 200},
{name: "apple-2332", views: 200},
{name: "samsung-6543", views: 400},
{name: "samsung-9876", views: 600}
];
let result = array1.map(x => ({ name: x.name, total: array2.filter(a => a.name.includes(x.name)).length }));
console.log(result);You could take a map for counting the occurence and update array1.
var array1 = [{ name: "samsung", views: 1200 }, { name: "apple", views: 200 }],
array2 = [{ name: "samsung-1234", views: 200 }, { name: "apple-2332", views: 200 }, { name: "samsung-6543", views: 400 }, { name: "samsung-9876", views: 600 }];
types = new Map(array1.map(o => ([o.name, Object.assign(o, { types: 0 })])));
array2.forEach(({ name }) => ++types.get(name.split('-')[0]).types);
console.log(array1);.as-console-wrapper { max-height: 100% !important; top: 0; }
array1.map(el => {
return array2.filter(el2 => {
return el2.name.includes(el.name)
})
})
Does it help you?
I'm not entirely sure I understand the significance of the first array, but you can get the number of items with Samsung with a simple for loop.
let cnt = 0;
array2.forEach((val) => {if (val.name.match(/samsung/i)) { cnt++}})
console.log(cnt) // 3
array1 = [
{name: "samsung", views: 1200},
{name: "apple", views: 200}
]
array2 = [
{name: "samsung-1234", views: 200},
{name: "apple-2332", views: 200},
{name: "samsung-6543", views: 400},
{name: "samsung-9876", views: 600}
]
const result = array1.map(brand => {
let howManyTypes = array2.filter(ele => ele.name.indexOf(brand.name) != -1).length;
return {name: brand.name, howManyTypes}
})
console.log(result)