Send values to $_GET using jQuery

Question

I'm using a PHP script that is waiting for two values through $_GET.

I'm trying to pass those 2 values using jQuery and that's where I'm not too good at.

Here's the code I've got.

Can somebody point me in the right direction ? Thanks !

function xrate(id,rating){  

   $.ajax({
      url: "ajax_xrate.php?id="+id+"&rate="+rating,
      global: false,
      type: "GET",
      dataType: "text",
      async:false,
      success: function(){
         alert('Bravo!');
      }
   });

}

(actual code copied from the comments)

function xrate(id,rating){ 
    var oDate = new Date(); 
    $.ajaxSetup({ cache: false }); 
    $.ajaxSetup({ 
        scriptCharset: "utf-8" ,
        contentType: "application/x-www-form-urlencoded; charset=UTF-8" 
    }); 
    $.ajax({
        url: 'ajax_xrate.php?timestamp='+oDate.getMilliseconds(), 
        dataType: 'html', 
        data: {itemid:id, keyrate:rating}, 
        cache: false, 
        type: "GET", 
        success : function(dataReturn){ 
            alert(dataReturn); 
        } 
    }); 
}

And what exactly is happening? Do you have a problem? My guess would be problems with parameter encoding (and async:false is a bad idea). — Felix Kling
– Felix Kling, Commented Mar 2, 2011 at 18:39
My code is actually this : function xrate(id,rating){ var oDate = new Date(); $.ajaxSetup({ cache: false }); $.ajaxSetup({ scriptCharset: "utf-8" ,contentType: "application/x-www-form-urlencoded; charset=UTF-8" }); $.ajax({ url: 'ajax_xrate.php?timestamp='+oDate.getMilliseconds(), dataType: 'html', data: {itemid:id,keyrate:rating}, cache: false, type: "GET", success : function(dataReturn){ alert(dataReturn); } }); } On this other side, I'm echoing the values with $print_r($_GET); But I don't get anything echoed ... — Alex
– Alex, Commented Mar 2, 2011 at 20:11

hsz · Accepted Answer · 2011-03-02 18:35:57Z

2

function xrate(id,rating){  

   $.ajax({
      url: "ajax_xrate.php",
      data: {
          id: id,
          rate:rating
      },
      type: "GET",
      success: function(){
         alert('Bravo!');
      }
   });

}

answered Mar 2, 2011 at 18:35

hsz

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2 Comments

Alex Over a year ago

Hi hsz, thanks for your quick answer !! Although I'm pretty sure your answer is correct, I can't seem to be able to make it work. How should I get the values in the PHP script ? $id_value = $_GET['id']; $rate_value = $GET['rate']; Would it be correct ? Also, how can I use "echos" in my PHP script to help be debug, and see the results appear in the webpage ?

einstein Over a year ago

@user641747: To get the values is correct that you mentioned. To debug in webpage, although I don't recommend it. You use success: function(text){ // use the text parameter to see any reporting }

Naftali · Accepted Answer · 2011-03-02 18:43:54Z

1

you can do:

function xrate(id,rating){  

   $.get("ajax_xrate.php",
      {
          'id': id,
          'rate': rating
      }, 
     function(){
       alert('Bravo!')
     }
  );

}

answered Mar 2, 2011 at 18:43

Naftali

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Comments

Praveen Prasad · Accepted Answer · 2011-03-02 19:00:22Z

0

jquery.ajax work like this

jQuery.ajax({
   url:'you_ur',
   type:'GET'  or 'POST',
   data:{prop1:value1},  // name value pair of props waiting on server
   //etc etc here
});

http://api.jquery.com/jQuery.ajax/

answered Mar 2, 2011 at 19:00

Praveen Prasad

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Comments

einstein · Accepted Answer · 2011-03-02 19:14:24Z

0

function xrate(id,rating){  

   $.ajax({
          url: "ajax_xrate.php",
          data: "id="+id+"&rate="+rating,
          async:false,
          success: function(){
             alert('Bravo!');
          }
   });

}

You don't need set parameters like type = 'get' because they are already default. Every parameters shall be inputed in the data: either in string form(like the one above) or object form({id: '45', rate: 'something'}). Async is also true on default in case you didn't know

answered Mar 2, 2011 at 19:14

einstein

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