How to extract output from async function - react-native?

Question

I have got a question. How do I get a result from function a async function?

This is my code:

function kakaoLogin() {
  return async dispatch => {
    RNKakaoLogins.login((err, result) => {
      console.log(result);
    });
    console.log(result);
  };
}

this is result.

The first console.log(result) shows token!. but second console.log(result) does not show anything.

I want to get same result from second console.log(result) as first console.log(result)

Khemraj Sharma · Accepted Answer · 2018-08-10 12:24:08Z

2

function kakaoLogin() {
  return async dispatch => {
    RNKakaoLogins.login((err, result) => {
      console.log(result);
    });
    console.log(result); // calling result outside its scope will not work
  };
}

What do you expect with a null result? You are using result outside of block. If you want to do something in response. then you can make method call like.

function kakaoLogin() {
  return async dispatch => {
    RNKakaoLogins.login((err, result) => {
      console.log(result);
      doSomeWork(result);
      // you can call another method here when you get response.
    });
  };
}

function doSomeWork(result){
.. somework
}

answered Aug 10, 2018 at 12:24

Khemraj Sharma

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6 Comments

Bojan Bedrač Over a year ago

Also you shouldn't be using an async result immediately after issuing an async call. You should be using a callback like @Khemraj suggests or a then() method for better readability.

박형렬 Over a year ago

I want to get token value from second console.log(result) like first console.log(result)

Bojan Bedrač Over a year ago

The first console.log(result); is executed after the async method resolves with the result. The second console.log(result); is executed with the result variable being undefined.

Khemraj Sharma Over a year ago

How will you use response when response did not come?

Bojan Bedrač Over a year ago

Your code executes like this RNKakaoLogins.login -> second console.log(result); -> RNKakaoLogins.login returns result -> first console.log(result);

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