Shell script takes variable as a command

Question

I'm coding an extremely simple shell script and it doesn't really work as it should. Here are the contents:

# Defining base project directory
BASE_DIR=/path/to/proj;
PRODUCTION_DIR = $BASE_DIR/out/production/dir;

# Generating headers
javah -classpath $PRODUCTION_DIR -d $BASE_DIR/jni/include com.my.class.Name

#     Building native libs
ndk-build

Paths are correct, it works if I remove $PRODUCTION_DIR, if I'll run it like this, it says:

line 3: PRODUCTION_DIR: command not found
...

Does any one know what's wrong?

If this is a bash or dash or sh script, you do not need to (and probably shouldn't) terminate lines with semicolons. — ithcy
– ithcy, Commented Mar 4, 2011 at 17:48

Erik · Accepted Answer · 2011-03-04 17:48:36Z

7

Remove whitespace,

PRODUCTION_DIR=$BASE_DIR/out/production/dir

Otherwise you're trying to run PRODUCTION_DIR with parameters = and $BASE_DIR/out/production/dir

Also, remove the ;'s at end of line, they're redundant

answered Mar 4, 2011 at 17:48

Erik

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4 Comments

Noufal Ibrahim Over a year ago

+1 and also, you should be using a build tool like make for this kind of thing. Not a shell script.

Denys S. Over a year ago

@Noufal Ibrahim, to generate headers from java sources and compile ndk project... make?

Noufal Ibrahim Over a year ago

I'm not at all familiar with java and have no experience with the ecosystem but I'm guessing that you're doing some kind of build and so recommend a build system like make (which is what I'm used to).

ithcy Over a year ago

"if you want to change the oil in your car, you should first learn how to build a car repair shop."

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