Simplify for loop in python

Question

I am using python and asking for help on how to simplify the code below. Thanks.

for i in range(1,9):
    if i == 1:
        wt_1 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 2:
        wt_2 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 3:
        wt_3 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 4:
        wt_4 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 5:
        wt_5 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 6:
        wt_6 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 7:
        wt_7 = gwt_2018[gwt_2018.WkNum == i]
    else i == 8:
        wt_8 = gwt_2018[gwt_2018.WkNum == i]

Let's start with synthax: gwt_2018.WkNum == i will be evaluated to either True or False. Is that your intent? Does gwt_2018 have a True or False key? — Chillie
– Chillie, Commented Aug 24, 2018 at 8:28
Are we supposed to guess what gwt_2018 is and what this code is supposed to do ? — bruno desthuilliers
– bruno desthuilliers, Commented Aug 24, 2018 at 8:57

Joe · Accepted Answer · 2018-08-24 08:27:43Z

0

Do you need something like this?

l = [wt_1, wt_2, wt_3, wt_4, wt_5, wt_6, wt_7, wt_8]
for index, i in enumerate(l):
    i = gwt_2018[gwt_2018.WkNum == index+1]

answered Aug 24, 2018 at 8:27

Joe

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Comments

Tony Pellerin · Accepted Answer · 2018-08-24 08:34:19Z

0

Is that mandatory to have 'wt_i' as variable name for all i's ?

I would use a dictionary instead:

wt = {}
for i in range(1,9):
    wt[i] = gwt_2018[gwt_2018.WkNum == i]

answered Aug 24, 2018 at 8:34

Tony Pellerin

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1 Comment

chazaq cruz Over a year ago

Thank you for the quick reply. I did find the solution for my problem. gbl = globals() for i in range(1,54): gbl['df_'+str(i)] = gwt_2018[gwt_2018.WkNum == i]

chazaq cruz · Accepted Answer · 2018-08-24 09:01:08Z

0

I found the solution [a link] (Create multiple dataframe using for loop in python 2.7)

gbl = globals()
for i in range(1,54):
    gbl['df_'+str(i)] = gwt_2018[gwt_2018.WkNum == i]

answered Aug 24, 2018 at 9:01

chazaq cruz

1

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