overloading methods in python class [duplicate]

Question

I tried to add numpy arrays in method overloading but got error like TypeError: add() missing 1 required positional argument: 'n3'

import numpy as np
class addition:
    def add(self,n1,n2):
        return n1+n2
    def add(self,n1,n2,n3):
        return n1+n2+n3
s=np.array([[1,2,3],[3,4,4]])
s1=np.array([[1.0,2,3],[3,4,4]])
s3=np.array([[1.0,2.4,3.7],[3,4,4]])
c=addition()
print(c.add(1,2))

There is no such thing as method overloading in Python. Only the second version actually wins. — Martijn Pieters
– Martijn Pieters, Commented Sep 3, 2018 at 11:54
See the duplicate on how to define methods that can take a variable number of arguments. — Martijn Pieters
– Martijn Pieters, Commented Sep 3, 2018 at 11:55
@MartijnPieters Not sure why, but only the 5th answer in the dup (by upvotes) mentions star arguments. — DeepSpace
– DeepSpace, Commented Sep 3, 2018 at 11:57
@DeepSpace: that's just one way of accepting a variable number of arguments. *args is only useful if you want to accept any number of arguments, from 0 to sys.maxsize. It's not always the right choice. — Martijn Pieters
– Martijn Pieters, Commented Sep 3, 2018 at 11:58

DeepSpace · Accepted Answer · 2018-09-03 11:54:42Z

0

Python does not support overloading. The actual method will be the one that was defined the latest, as the error you get suggests.

Instead, use *args:

def add(self, *args):
    return sum(args)

answered Sep 3, 2018 at 11:54

DeepSpace

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