Python - clicking on button with Selenium

Question

This is the button I'm trying to click:

<button class="stkv-c-button stkv-us-button-color--background 
    stkv-u-background-color-transition-150 
    stkv-us-button-color--border stkv-us-button-color 
    stkv-us-button-color--fill stkv-c-button 
    stkv-c-button--raised stkv-c-button--big">

    <span class="stkv-c-button__label stkv-c-button__label--big">Vote Now</span>
</button>

This is the xpath (pulled from Firefox):

[@id='root']/html/body/div/div/div[3]/div/div/footer/div/button"

I've tried a wide variety of ways to click on the button, all to no avail.

self.driver.find_element_by_xpath("//*[@id='root']/html/body/div/div/div[3]/div/div/footer/div/button").click()
self.driver.findElement(By.id("Vote Now")).click()
self.driver.find_element_by_name("Vote").send_keys(Keys.ENTER)
self.driver.find_element_by_id('stkv-c-button stkv-us-button-color--background stkv-u-background-color-transition-150 stkv-us-button-color--border stkv-us-button-color stkv-us-button-color--fill stkv-c-button stkv-c-button--raised stkv-c-button--big').click()

Any suggestions would be greatly appreciated!

I'm not having any luck with it.

What happens when you try to use that code? Does it throw an ElementNotFound exception? — John Gordon
– John Gordon, Commented Sep 24, 2018 at 0:05

yong · Accepted Answer · 2018-09-24 00:25:56Z

1

You can find the button by display text on it.

locator = "//button[span[text()='Vote Now']]"
self.driver.find_element_by_xpath(locator).click()

answered Sep 24, 2018 at 0:25

yong

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Comments

zachrellim · Accepted Answer · 2018-09-24 01:18:45Z

Your button doesn't have an id or name, so the find_element_by_name and find_element_by_id methods will not work. find_element_by_class_name seems like the logical choice, but unfortunately it only expects only 1 class, and since your button has multiple classes, it won't work either. I would try locating the button with its CSS selector:

self.driver.find_element_by_css_selector('button.stkv-c-button.stkv-us-button-color--background.stkv-u-background-color-transition-150.stkv-us-button-color--border.stkv-us-button-color.stkv-us-button-color--fill.stkv-c-button.stkv-c-button--raised.stkv-c-button--big').click()

As long as there isn't another button on the page with the exact same CSS selector, this should give you the correct button. In general, if you want to find an element that has multiple classes, e.g. <button class="A B C">MyButton</button>, then you could do it with:

self.driver.find_element_by_css_selector('button.A.B.C')

iamsankalp89 · Accepted Answer · 2018-09-24 05:03:40Z

1

Use this XPath : //button[normalize-space()='Vote Now']

edited Sep 24, 2018 at 5:03

iamsankalp89

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answered Sep 24, 2018 at 4:00

Pritam Maske

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Comments

undetected Selenium · Accepted Answer · 2018-09-24 05:56:18Z

1

As per the HTML you have shared to click() on the button with text as Vote Now you can use either of the following solution:

CSS_SELECTOR:

driver.find_element_by_xpath("span.stkv-c-button__label.stkv-c-button__label--big").click()

XPATH:

driver.find_element_by_css_selector("//span[@class='stkv-c-button__label stkv-c-button__label--big' and contains(.,'Vote Now')]").click()

answered Sep 24, 2018 at 5:56

undetected Selenium

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