Bash expand variable in an another variable [duplicate]

Question

I have the following variables

my_country_code="green"
x="country"

echo ${my_$x_code}
bash: ${my_$x_code}: bad substitution

echo should print green as output, but unable to find any technique which will give the correct output

x=country; declare "my_${x}_code=green"; var="my_${x}_code"; echo "${!var}" — Inian
– Inian, Commented Sep 27, 2018 at 3:07

Chris Dodd · Accepted Answer · 2018-09-27 03:03:52Z

4

my_x_code="my_${x}_code"
echo ${!my_x_code}

answered Sep 27, 2018 at 3:03

Chris Dodd

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1 Comment

Charles Duffy Over a year ago

Do keep in mind the note re: questions which "...have already been asked and answered many times before" in the "Answer Well-Asked Questions" section of How to Answer

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