Dynamically add key value pair in jSON object using shell

Question

I have a json object named version6json as follows

{
  "20007.098": {
    "os_version": "6.9",
    "kernel": "2.6.32-696",
    "sfdc-release": "2017.08"
  },
  "200907.09678”: {
    "os_version": "6.9",
    "kernel": "2.6.32-696",
    "sfdc-release": "201.7909"
  },
  "206727.1078”: {
    "os_version": "6.9",
    "kernel": "2.6.32-696.10.2.el6.x86_64",
    "sfdc-release": "20097.109”
  }
}

I want to add one more key value pair. The key is also a variable and the value too. bundle_release="2019.78" and value= {"release":"2018.1006","kernel":"2.6.32-754.3.5.el6.x86_64","os":"6.10","current":true} Now I want the bundle_release as key and value as its value, So the new entry would be "2018.1006": {"release":"2018.1006","kernel":"2.6.32-754.3.5.el6.x86_64","os":"6.10","current":true}

To achieve this, I am doing the folllowing

echo "$version6json" | jq --arg "$bundle_release" "$value" '. + {$bundle_release: "${value}"}'

Any help will be appriciated.

P.S- The question is edited as suggested by peak

bundle_release="1034,567" I want to use this as key and a value against it. The value is {"release":"2018.1006","kernel":"2.6.32-754.3.5.el6.x86_64","os":"6.10","current":true} This I am fetching from items array. Thats why "${items[$i-1]}" , it is the value. — sillydeedee
– sillydeedee, Commented Oct 24, 2018 at 11:44
Please fix the JSON. ” should be replaced by ". You can use jq to validate the JSON, e.g. jq empty <<< "$version6json" — peak
– peak, Commented Oct 24, 2018 at 20:20

peak · Accepted Answer · 2018-10-24 20:52:05Z

2

First, when specifying a key name using a variable in the way you are doing, the variable must be parenthesized, so you would have:

 {($bundle_release): ...}

Next, jq variables are not the same as shell variables and should be specified without quoting them, and without using bash-isms.

Third, when setting the value of the shell variable named value, you would have to quote the expression appropriately.

Fourth, to simplify things, use --argjson for $value.

Fifth, your sample JSON is not quite right. Once it's fixed, the following will work in a bash or bash-like environment (assuming you're using a version of jq that supports --argjson):

bundle_release="1034,567"
value='{"release":"2018.1006","kernel":"2.6.32-754.3.5.el6.x86_64","os":"6.10","current":true}'

jq --arg b "$bundle_release" --argjson v "$value"  '
  . + {($b): $v}' <<< "$version6json"

edited Oct 24, 2018 at 20:52

answered Oct 24, 2018 at 9:19

peak

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4 Comments

sillydeedee Over a year ago

I think I am not clear to u about my question. bundle_release is a variable having some value , I want to use this variable as a key and some other variable (say value) as value. The result you provided is not giving desired result. It is giving key and value same.

peak Over a year ago

Your example only had one shell variable, so I used that. You could use —arg value "$value" for the other value, and then use $value for the value.

sillydeedee Over a year ago

So if bundle_release="2098.09" is key and value={ "os_version": "6.9", "kernel": "2.6.32-696.23.1.el6.x86_64", "sfdc-release": "2018.0505" } then the command would be--> . jq --arg bundle_release value '. + {($bundle_release): $value}' . I tried this but not working

peak Over a year ago

The answer has been updated in accordance with the updated question.

glenn jackman · Accepted Answer · 2020-06-20 09:12:55Z

1

You're not giving the --arg option enough parameters: from the manual:

--arg name value:

This option passes a value to the jq program as a predefined variable. If you run jq with --arg foo bar, then $foo is available in the program and has the value "bar". Note that value will be treated as a string, so --arg foo 123 will bind $foo to "123".

edited Jun 20, 2020 at 9:12

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