I have the following array
// Exmaple
[
['morning', 'afternoon'],
['morning'],
['morning', 'afternoon'],
['morning', 'afternoon'],
['morning']
]
I may have the same one but with afternoon in every array.
I need to check if a given value exists in all arrays, for example if I check for 'morning' it should return true, but if I check for 'afternoon' it should return false because in the example array above not all of them have 'afternoon'
array.every(day => day.includes("morning")) // true
You can use .every() and .includes() methods:
let data = [
['morning', 'afternoon'],
['morning'],
['morning', 'afternoon'],
['morning', 'afternoon'],
['morning']
];
let checker = (arr, str) => arr.every(a => a.includes(str));
console.log(checker(data, 'morning'));
console.log(checker(data, 'afternoon'));You can use Array.every and Array.includes
let arr = [['morning', 'afternoon'],['morning'],['morning', 'afternoon'],['morning', 'afternoon'],['morning']];
console.log(arr.every(v => v.includes('morning'))); // true
console.log(arr.every(v => v.includes('afternoon'))); // false
use .every()
array.every(d => d.includes("morning")) // true
array.every(d => d.includes("afternoon")) //false
You can use Array.prototype.every() and coerces to boolean the result of Array.prototype.find() which returns the value of the first element in the array that satisfies the provided testing function. Otherwise undefined is returned.
Code:
const data = [['morning', 'afternoon'],['morning'],['morning', 'afternoon'],['morning','afternoon'],['morning']];
const checker = (arr, str) => arr.every(a => !!a.find(a => str === a));
console.log(checker(data, 'morning'));
console.log(checker(data, 'afternoon'));
