Javascript object values returning as [object,object]

Question

I have a javascript object like the following:

var Numeric_values = {
US:  {01: "202-555-0151", 02: "202-555-0167", 03: "202-555-0150"},
CAD: {01: "613-555-0144", 02: "613-555-0192", 03:"613-555-0151"},
AUS: {01: "1900 654 321"}
};

I am attempting to access all of the values of this object and listing them out as a string like this:

"202-555-0151","202-555-0167", "202-555-0150"
"613-555-0144", "613-555-0192","613-555-0151"
"1900 654 321"

I have so far attempted to use Object.values(Numeric_Values) and

for (let key in Numeric_values){
      console.log(Numeric_values[key]);
  }

and these always return as [object,object], how can i fix this?

And how is textOut() defined? That's what you should have showed in your attempt. — Patrick Roberts
– Patrick Roberts, Commented Nov 16, 2018 at 21:48
Sorry, i edited it out. For the purpose of this it functionally works as console.log(). — Necropants
– Necropants, Commented Nov 16, 2018 at 21:56

Akrion · Accepted Answer · 2018-11-16 21:57:11Z

3

You can print/access them via Object.values and Array.forEach:

var data = {
  US: {
    01: "202-555-0151",
    02: "202-555-0167",
    03: "202-555-0150"
  },
  CAD: {
    01: "613-555-0144",
    02: "613-555-0192",
    03: "613-555-0151"
  },
  AUS: {
    01: "1900 654 321"
  }
};

Object.values(data).forEach(x => console.log(...Object.values(x)))

You could also recursively get the values like so:

var data = {
  US: {
    01: "202-555-0151",
    02: "202-555-0167",
    03: "202-555-0150"
  },
  CAD: {
    01: "613-555-0144",
    02: "613-555-0192",
    03: "613-555-0151"
  },
  AUS: {
    01: "1900 654 321"
  }
};

const flatten = (obj, a = []) => Object.values(obj)
  .reduce((r, c) => (typeof c == 'object' ? flatten(c, a) : r.push(c), r), a)

console.log(...flatten(data))

edited Nov 16, 2018 at 21:57

answered Nov 16, 2018 at 21:50

Akrion

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4 Comments

Necropants Over a year ago

Thanks a lot! that is exactly what i needed, how does .map work differently from what i have been doing though?

slider Over a year ago

You don't need map since you don't intend to create a new array. forEach is more appropriate.

Kapil gopinath Over a year ago

You can use forEach

Akrion Over a year ago

forEach it is. Thanks.

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