In Python, you'd do:
from operator import attrgetter
map(lambda x: x.name,
sorted(filter(lambda x: x.count > 10, someArray),
key=attrgetter("count"))
Syntax is slightly different, but it should basically do the same. Does this answer your question?
Edit
If you really want a more "chain-like" syntax, you can take a look at toolz. From their docs:
>>> from toolz.curried import pipe, map, filter, get
>>> pipe(accounts, filter(lambda acc: acc[2] > 150),
... map(get([1, 2])),
... list)
Edit 2
Thanks to @mpium for suggesting PyFunctional, which seems to have an even cooler syntax for this:
from functional import seq
seq(1, 2, 3, 4)\
.map(lambda x: x * 2)\
.filter(lambda x: x > 4)\
.reduce(lambda x, y: x + y)
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