i'm trying to use includes to see if an object is inside the array like so:
arr=[{name:'Dan',id:2}]
and I want to check like so:
arr.includes({name:'Dan',id:2})
and this returns false, is there a way to do that?
i'm trying to use includes to see if an object is inside the array like so:
arr=[{name:'Dan',id:2}]
and I want to check like so:
arr.includes({name:'Dan',id:2})
and this returns false, is there a way to do that?
does include works with array of objects?
Yes — if you use the same object as the argument to includes that's in the array:
const obj = {name: "Dan", id: 2};
const arr = [{name: "T.J.", id: 42}, obj, {name: "Joe", id: 3}];
console.log(arr.includes(obj)); // true
console.log(arr.includes({name: "Dan", id: 2})); // false
includes uses a === check, and o1 === o2 is only ever true when o1 and o2 refer to the same object. In your example, you're using two different but equivalent objects instead.
For your use case, you probably want some, which lets you execute a callback to determine whether an entry in the array matches a condition:
if (arr.some(e => e.id === 2)) {
Example:
const obj = {name: "Dan", id: 2};
const arr = [{name: "T.J.", id: 42}, obj, {name: "Joe", id: 3}];
console.log(arr.some(obj => obj.id === 2)); // true
There are various ways to spin that, depending on what you want the check to be (which are discussed at length in this question's answers), but that just means adjusting the contents of the function you pass some.
:) I had the same question. By reference vs Value right?includes is === (which I should have said above, and will :-)). o1 === o2 is only ever true when o1 and o2 both contain references to the same object. (Variables hold object references, which are values. Though there are other interpretations...)Arrays do have includes() function, but for your case, you have to do using some():
arr.some(e => e.id === 2 && e.name === "Dan")
arr.some(e => e.name === "Dan")
some, which suggests when you find you're posting it for the third time, probably best to delete.:)