php - Compare arrays with duplicated values

Question

I need to compare (without remove ANY value) 2 arrays BUT each of these arrays can have duplicated values so for e.g. I have those 2 arrays:

$options = ['G', 'W'];
$selectedOptions = ['G', 'G', 'W'];

This should return FALSE. Below is my code which I have. It works good but only for unique values, how to 'upgrade' it for duplicated values?

$mergeOptions = array_merge($selectedOptions, $options);
$intersect = array_intersect($selectedOptions, $options);
$diff = array_diff($mergeOptions, $intersect);

if (count($diff) === 0) {
    // $options are 'equal' to $selectedOptions
} else {
    // $options are not 'equal' to $selectedOptions
}

More examples:

| selected | options | result |  
+----------+---------+--------+  
|  G, G, W |  G, W   |  FALSE |
+----------+---------+--------+
|   G, W   |  G, W   |  TRUE  |
+----------+---------+--------+
| G, P, W  | G, G, W |  FALSE |
+----------+---------+--------+
| G, P, G  | P, G, G |  TRUE  |
+----------+---------+--------+

Not clear what you want to do with or because of these duplicates — RiggsFolly
– RiggsFolly, Commented Dec 17, 2018 at 13:46
$options = ['G', 'W'];, $selectedOptions = ['P', 'G', 'W']; is result true or false ? — Cid
– Cid, Commented Dec 17, 2018 at 13:47
@RiggsFolly This not exactly duplicate because here he doesn't want to remove them but to compare even if duplication exists — dWinder
– dWinder, Commented Dec 17, 2018 at 13:57
Are you sure @DavidWinder ? Seems the simplest route to a solution — RiggsFolly
– RiggsFolly, Commented Dec 17, 2018 at 13:58

dWinder · Accepted Answer · 2018-12-17 13:58:07Z

3

You can sort the arrays with sort and then compare them.

$a = ["P", "G", "G"];
$b = ["G", "P", "G"];
sort($a);
sort($b);

if ($a == $b) {
    echo "TRUE \n";
} else {
    echo "FALSE... \n";
}

answered Dec 17, 2018 at 13:58

dWinder

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1 Comment

Cid Over a year ago

Sort is a good idea, I was en route to post an answer with array_count_values() when Riggs closed the question

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