Object Values sorting with umulate order

Question

I have been trying to sort the json response object array in specific order like if the object contains Umlaute words/characters

object {
  item: 1,
  users: [
   {name: "A", age: "23"}, 
   {name: "B", age: "24"},
   {name: "Ä", age: "27"}
 ]
}

Expected name sorting is A, Ä and B.

when trying to sort with localecompare().

object.sort(function (a, b) { return a.localeCompare(b); });

Getting the error like object.sort is not a function. Is there anyway to sort the object array.

no you cannot do that. sort is an array method and you can never guarantee the order of object keys — brk
– brk, Commented Jan 2, 2019 at 14:17
Looking at your example, You do have an array of objects and it is possible to sort this array using sort. Shouldn't you do object.users.sort((a,b) => a.name.localeCompare(b.name)). — Boopathi Rajaa
– Boopathi Rajaa, Commented Jan 2, 2019 at 14:21
I have tried object.users.sort((a,b) => a.name.localeCompare(b.name)) but throws an error like a.localeCompare is not a function — klmuralimohan
– klmuralimohan, Commented Jan 2, 2019 at 14:23
it's a.name.localeCompare(b.name)) not a.localeCompare(b.name)) — Mohit Patil
– Mohit Patil, Commented Jan 2, 2019 at 14:28

Nina Scholz · Accepted Answer · 2019-01-02 14:21:46Z

2

You need to take the property of the object for sorting.

var object = { item: 1, users: [{ name: "A", age: "23" }, { name: "B", age: "24" }, { name: "Ä", age: "27" }] };

object.users.sort(function (a, b) { return a.name.localeCompare(b.name); });

console.log(object);

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Jan 2, 2019 at 14:21

answered Jan 2, 2019 at 14:19

Nina Scholz

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3 Comments

brk Over a year ago

how do you know he want to sort the user?

Nina Scholz Over a year ago

@brk, "Expected name sorting is A, Ä and B. ".

Nina Scholz Over a year ago

@klmuralimohan, does the above works for you? do you use a.localeCompare? a is an object, not a string, like name.

pid · Accepted Answer · 2019-01-02 14:37:10Z

You must apply the sort() function to the array, not the outer object. Objects don't have that method and in the general case key order is not guaranteed, anyways. For "ordered" data always use arrays, not objects!

This is an example that uses the o.users array. The output n is also an array.

NOTE: never abuse reserved keywords as variable names. You use object as a variable name, it is strongly recommended to not do so! I've replaced it with o. Albeit object is not a reserved keyword, Object (with capital O) is. And the two are easily confused.

var o = {
  "item": 1,
  "users": [
    { "name": "A", "age": "23" },
    { "name": "B", "age": "24" },
    { "name": "Ä", "age": "27" }
  ]
};

var n = o.users.sort((a, b) => a.name.localeCompare(b.name, "de"));

console.log(n);

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