Replace affects all strings in an array

Question

I am having some issues about replacing. I am fetching some integers from DB. And if the number fetched is just 1 then I replace it with "empty", but when I do that, it affects all numbers that have 1 in them.

Here is what I am doing, first calling toString and then replace

<tr v-if="moreIndex < one.length"　 v-for="moreIndex in morePro">
  <td>{{one[moreIndex].products}}</td>
  <td>{{priceSep(one[moreIndex].price).toString().replace("1", "empty")}}</td>
</tr>

So I am changing "1" to empty but if any other data has includes 1 then output look like this...

5empty98

How can I fix this problem?

If you get the input "1" you want to change it to "empty", but if you get "something1", you do not want to touch it all? Could you provide inputs and expected values? — Alberti Buonarroti
– Alberti Buonarroti, Commented Feb 17, 2019 at 10:18

Mamun · Accepted Answer · 2019-02-18 11:40:02Z

1

You can check the length with Conditional (ternary) operator .:

<td>{{priceSep(one[moreIndex].price).toString().length == 1 ? priceSep(one[moreIndex].price).toString().replace("1", "empty") : priceSep(one[moreIndex].price).toString()}}</td>

May be, you can try directly set the value if the value is 1:

<td>{{priceSep(one[moreIndex].price).toString() == "1" ? "empty" : priceSep(one[moreIndex].price).toString()}}</td>

edited Feb 18, 2019 at 11:40

answered Feb 17, 2019 at 10:28

Mamun

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Comments

brk · Accepted Answer · 2019-02-17 10:29:59Z

0

You can check the length of the string before replacing it

{{priceSep(one[moreIndex].price).toString().length > ? 
  priceSep(one[moreIndex].price).toString() :
  priceSep(one[moreIndex].price).toString().replace("1", "empty")
}}

answered Feb 17, 2019 at 10:29

brk

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Comments

Jigius · Accepted Answer · 2019-02-17 16:17:34Z

0

You can use RegExp:

{{priceSep(one[moreIndex].price).toString().replace(/^1$/, "empty")}}

answered Feb 17, 2019 at 16:17

Jigius

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