How to replace using a regexp from the terminal

Question

I want to replace in index.html using one of the default debian linux tool the following:

="([A-z]+).html"

with

="javadoc/$1.html"

index.html file contains the following:

<frame src="overview-frame.html" name="packageListFrame" title="All Packages">
<frame src="allclasses-frame.html" name="packageFrame" title="All classes and interfaces (except non-static nested types)">
</frameset>
<frame src="overview-summary.html" name="classFrame" title="Package, class and interface descriptions" scrolling="yes">
Link to <a href="overview-summary.html">Non-frame version</a>.</p>

I have started using sed but I have expression error:

sed -E 's,="([^"]+)\.html",="javadoc\/\1.html",' public/javadoc/index.html

"I want to replace" (what?) "in index.html ..." and sed -E "s/=\"([A-z-]+)\"/\1something\2/" has only 1-capture but uses \1...\2 (e.g. 2) backreferences?? — David C. Rankin
– David C. Rankin, Commented Mar 27, 2019 at 15:06
Try sed -E 's,="([^"]+)\.html",javadoc/\1.html,' public/javadoc/index.html — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Mar 27, 2019 at 15:07

UtLox · Accepted Answer · 2019-03-27 16:49:43Z

1

try this:

sed "s/\([^\"]*\.html\)/javadoc\/\1/g" public/javadoc/index.html

explanation

s/                # substitute
\(                # start arg1
[^\"]*\.html      # all char before .html without "
\)                # end of arg1
/javadoc\/\1      # replace with javadoc/arg1
/g                # global on whole line

answered Mar 27, 2019 at 16:49

UtLox

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Comments

user7712945 · Accepted Answer · 2019-04-18 06:46:38Z

1

I don't get it yours perfectlly correct

sed -E 's,="([^"]+)\.html",="javadoc/\1.html",' public/javadoc/index.html

answered Apr 18, 2019 at 6:46

user7712945

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