How to access array in another page after sending through ajax

Question

I have a array student. I need to pass this array in another php page via POST, not from GET, because it can contains thousands of characters.

I am trying to open new page sheet.php and echo the array student, I do simply checking echo $_POST['mnu'], but it is showing undefined index error.

var http = null;
if(window.XMLHttpRequest){
    http = new XMLHttpRequest();
}
else{
    http = new ActiveXObject('Microsoft.XMLHTTP');
}
http.open('POST','sheet.php',true);
http.setRequestHeader('Content-type','application/x-www-form-urlencoded');
http.onreadystatechange = function(){
    if(http.readyState==4 && http.status==200){
        window.open('sheet.php','_blank')
    }
}
http.send('mnu='+JSON.stringify(student));

surely the above will effectively make 2 requests to sheet.php - a POST request and then, when that succeeds, a GET request? — Professor Abronsius
– Professor Abronsius, Commented Apr 14, 2019 at 21:08
if you are using jquery just use this without the above code $.post('sheet.php',{mnu:student},function() {window.open('sheet.php','_blank')}); — Talal
– Talal, Commented Apr 14, 2019 at 21:33
@Talal, I tried using $.post, it redirects but same problem undefined index $_POST['mnu']. Is there any other way to access ?? I am doing simply if(isset($_POST['mnu'])){echo $_POST['mnu'];} — Hemant
– Hemant, Commented Apr 14, 2019 at 21:42
dude the ajax request would have data posted after the success of the request it would open sheet.php and this time there is no data posted — Talal
– Talal, Commented Apr 14, 2019 at 21:46

Levi Cole · Accepted Answer · 2019-04-14 22:19:32Z

Like @RamRaider commented.. you're making two requests to sheet.php. The first being a "silent" POST request and the second being a GET request after the first POST request has successfully completed.

The second request won't share the payload of the first.

If I under stand correctly the below code should do what you are wanting...

// Create a form element
// <form action="sheet.php" method="post"></form>
var tempForm = document.createElement('form');
tempForm.setAttribute('action', 'sheet.php');
tempForm.setAttribute('method', 'POST');
tempForm.setAttribute('target', '_blank'); // Open in new tab

// Create an input field
// <input name="mnu" value="...">
var tempInput = document.createElement('input');
tempInput.setAttribute('name', 'mnu');
tempInput.setAttribute('value', JSON.stringify(student)); // Set field value

// Add the input to the form
tempForm.appendChild(tempInput);


// Add the form to the body in order to post
document.body.appendChild(tempForm);

// Submit the form
tempForm.submit();

// Remove the form
document.body.removeChild(tempForm);

And if you're using jQuery you can simplify the above code..

$('<form>', {
    action: 'sheet.php',
    method: 'POST',
    target: '_blank',
    html: $('<input>', {
        name: 'mnu',
        value: JSON.stringify(student)
    }).prop('outerHTML')
}).appendTo($('body')).submit().remove();

BusyChild77 · Accepted Answer · 2019-04-14 21:21:19Z

0

Change http.send('mnu='+JSON.stringify(student)); to http.send(JSON.stringify(student));

And then in your sheet.php use json_decode($_POST) to fetch your POST data

answered Apr 14, 2019 at 21:21

BusyChild77

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2 Comments

Hemant Over a year ago

what to decode in php file ??, json_decode() expects 1 parameter, and it doesn't student array

BusyChild77 Over a year ago

http.send(JSON.stringify(student)); means you turn your JSON object into a string. Once posted to the page sheet.php you need to turn it back to an object, so you can use something like $student = json_decode($_POST). Then you should be able to access your student directly as an object (e.g $student->name)

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