I thought the default value of boolean is false? Why does it print the true statement instead? My output is goodbye
public class Test {
public static void main (String [] args) {
if(false)
System.out.print("hello");
else System.out.print("goodbye");
}
}
Your code doesn't use the default value of boolean value.
You always print System.out.print("goodbye");, because this section is true.
To achieve this, use the following code
public class Test {
static boolean defaultValue;
public static void main(String[] args) {
System.out.println("Default value is "+defaultValue);
if(defaultValue)
System.out.println("hello");
else
System.out.println("goodbye");
}
}
What sweeper told you in a comment is correct. You seem to be under a wrong impression regarding the syntax I think. Take the following piece of code you gave as an example.
if (false) {
System.out.print("hello");
}
The code inside the if block will never run because the expression false will always evaluate to the boolean value false. You are asking Java to do the following: 'hey run this code if what I put inside the brackets evaluates to true but what you put inside the brackets will always evaluate to false. Thats why java will always run the code inside the else block in your example.
I hope this clears thing up a bit.
elsebranch executes if the expression inside the()evaluates tofalse, which it does in your code. What did you expect it to output? And can you explain why did you expect it to output that?truestatement? What happens? What did you expect?