Local variable problem in python, variable is not defines [duplicate]

Question

I am working on a project and keep getting variable not defined errors when I run the script. How can I solve this without declaring global variables

def func1():
    x = 1
def func2():
    y=5
    x + y = z
    print(z)

Error - Syntactical Remorse · Accepted Answer · 2019-06-04 16:24:53Z

1

x is in the local scope of func1, thus it can not be read from func2. You can use global x = 1 but I would not recommend it. Instead pass x to func2:

def func1():
    x = 1
    return x
def func2(x):
    y = 5
    z = x + y # You had this backwards as well (i.e. x + y = z)
    print(z)
x = func1()
func2(x)

edited Jun 4, 2019 at 16:24

answered Jun 4, 2019 at 16:20

Error - Syntactical Remorse

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2 Comments

glibdud Over a year ago

You'll also need to change x + y = z to z = x + y.

Error - Syntactical Remorse Over a year ago

Didn't even notice thank you.

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