Multidimensional array of functions

Question

How can I make this work:

q = {}

q[0] = new Array()

q[0].push(function()
{
   console.log("whatup")
})

q[0]() // currently prints "q[0] is not a function"

Of course, it shouldn't execute until I call it. I tried nesting it inside another function as a return value, but nothing works :(

Someone deleted their answer that had helpful information. You're actually creating an object filled with arrays, because you initialize q with {}, to create an array of arrays, use q = [] instead. — Jason LeBrun
– Jason LeBrun, Commented Apr 15, 2011 at 17:09

Jason LeBrun · Accepted Answer · 2011-04-15 17:06:43Z

6

You have a multidimensional array, but you're only accessing the first dimension at the end (which is another array). Try q[0][0]().

answered Apr 15, 2011 at 17:06

Jason LeBrun

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Comments

Matt Howell · Accepted Answer · 2011-04-15 17:06:39Z

3

The problem is that the value in q[0] is the new Array() that you assigned to it -- not a function.

These lines:

q[0].push(function()
{
   console.log("whatup")
})

will put the function as the first element of the new Array you assigned to q[0] in the second line. So instead of this:

q[0]() // currently prints "q[0] is not a function"

You're really wanting to do this:

q[0][0]()

answered Apr 15, 2011 at 17:06

Matt Howell

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6502 · Accepted Answer · 2011-04-15 17:07:44Z

2

Your code should work but you're calling the array. To call the function you need to do

q[0][0]()

answered Apr 15, 2011 at 17:07

6502

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